2x+7/3x^2+5x+8

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Solution for 2x+7/3x^2+5x+8 equation: 


x in (-oo:+oo)

(7/3)*x^2+2*x+5*x+8 = 0

7/3*x^2+7*x+8 = 0

DELTA = 7^2-(7/3*4*8)

DELTA = -77/3

DELTA < 0

x belongs to the empty set

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